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Wow, studs really knock down the net R-value!

17 years ago

I was doing some calculations about the net UA for my new home design, and so I needed to calculate the net R value for a wall or roof. Presuming a 1.5" stud every 16", that would mean a proportion of about .1 for the area of the stud. A 2x4 stud (i.e., 3.5" deep) has an R-value of 4.4.

So, if I had a nominal R-value of the wall (i.e., the non-stud part) of 19, then the net R-value would be:

net R = 1 / ( .9 / 19 + .1 / 4.4 ) = 14.3

Intuitively, it would seem that the net R-value should be about .1 of the way from 19 to 4.4, or about 18!

I wonder if when the energy efficiency organizations say that homeowners should have a certain R-value, that they mean that for the nominal application, or for the net as described. I'm barely going to be able to get a nominal R-value of 19 in a 2x4 wall!

Comments (13)

  • 17 years ago

    Without checking your calculations carefully, thermal bridging from the studs is a known problem. You are correct, it's tough to get the R19 in a 2x4 wall. Are you including an exterior insulating sheeting? Since that installs over the studs, it breaks the thermal bridging. I think a 1/2" of closed cell foam has an R 3.5 without looking it up.

    Other alt are going with 2x6 walls or using closed cell foam (or foam and bat). It doesn't solve the thermal bridging problem, but foam has about twice the R of fiberglass, provides a good air seal and (believe it or not) provides wracking and penetration resistance.

  • 17 years ago

    Yes, I'm going to go closed cell foam, with the exterior insulating sheeting.

  • 17 years ago

    There's some kind of sheathing, perhaps urethane, that gets R4. I actually double layered it on my western exposure, giving me R8 plus R13 for the pink stuff.It doesn't compress the fibreglass much. If you touch the inside of the wall at 7pm, it's not even warm.

  • 17 years ago

    Actually, I may go open cell on the walls, and use a 1/2" polyboard on the outside, that is R-3.5. That seems to be the best for the outside.

  • 17 years ago

    I'm not sure how you are designing the walls (vapor barrier, etc.) that said, open cell has about half the R value of closed cell while being more permeable.

    Are you sure about the R value of polyboard? I'm not familiar with it in practice, but what I was finding on the web didn't have that R value. That's the same as closed cell foil backed boards with low-R blowing agents (Tuff-R) which is about as high as an R value for 1/2" material as I can find for insulating sheeting.

  • 17 years ago

    I believe he is talking about polyisocyanurate board. It apparently runs from R6 to R8 per inch. My builder is planning to use doubled 1/2 inch polyisocyanurate insulating board between the sheathing and the siding. I forget which brand he is planning to use, but he said we should get R7 out of it.

    The house plans spec its use.

    Here is a link that might be useful: One Brand Of Polyisocyanurate Insulating Board

  • PRO
    6 years ago

    Your computation is wrong. 90% R19 and 10% R4.4 is R17.54 (.9*19 + .1*4.4)

  • 4 years ago
    last modified: 4 years ago

    His computations are correct. You use the harmonic mean, rather than the arithmetic mean, when calculating parallel resistance. Alternatively, convert R-values to u-values, calculate the average u-value, and then convert that average u-value back to an R-value.

    For example, if you had a wall where 20% was an R-value of 2, and the remaining 80% had an R-value of 20, then the R-value for the wall would be 7.14.

  • 4 years ago

    Styrofoam Green exterior use green board if building a new home .. R 10 for 2" thick $46 32 ft2. roughly 3x cost of R13 could cut 6" x 8' for base and then 2" strips for the studs if install time no issue. or just run in in full sheets also comes R5 at half cost ; 1" that'll make your stud R9.4 and wall R23. (net 1/ (.1/9.4 + .9/24) = R20.7 .

  • 4 years ago

    Then again what are the size and R value of your windows skylights etc.

  • 3 years ago

    Props to Matt Peterson for coming up with the most ridiculous reason the authors obvious calculation error is correct.

  • 3 years ago

    Please educate yourself: https://youtu.be/NAE6TOWz8nw?t=443


    The first author was correct: you transform the R values to U values (1/R), then take the weighted arithmetic mean. This is equivalent to the weighted harmonic mean of the R values.


    Theory: https://youtu.be/NAE6TOWz8nw?t=258